Remainder theorum

Sunny1982

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Mar 12, 2013
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can someone please check these and let me know if these are correct or if they are wrong can I have a few pointers or advise.

1. Determine the remainder when x³-6x²+x-5 is divided by:

a. X+2

f(x) = x³ - 6x² + x - 5
(x+2)= f(-2) = (-2)³ - 6(-2)² + (-2) - 5
-8 - 24 - 2 - 5 = -39

b. X-3

f(x)= x³ - 6x² + x-5
(x-3)=f(3)³ - 6(3)² + (3) - 5
27-72+3-5= -43
 
Last edited:
can someone please check these and let me know if these are correct or if they are wrong can I have a few pointers or advise.
b. X-3
f(x)= x³ - 6x² + x-5
(x-3)=f(3)³ - 6(3)² + (3) - 5
27-72+3-5= -43

The best pointers or advise anyone can give you is: learn to do basic arithmetic or don't make silly mistakes such as the one above.
 
The best pointers or advise anyone can give you is: learn to do basic arithmetic or don't make silly mistakes such as the one above.



Thankyou much appreciated

1. Determine the remainder when x³-6x²+x-5 is divided by:

a. X+2

f(x) = x³ - 6x² + x - 5
f(-2) = (-2)³ - 6(-2)² + (-2) - 5
-8 - 24 - 2 - 5 = -39

b. X-3

f(x)= x³ - 6x² + x-5
f(3)³ - 6(3)² + (3) - 5
27-54+3-5= -29

I believe this should be correct now sir?
 
Thankyou much appreciated

1. Determine the remainder when x³-6x²+x-5 is divided by:

a. X+2 <------- Use lower case for your whole problem/solution *

f(x) = x³ - 6x² + x - 5
f(-2) = (-2)³ - 6(-2)² + (-2) - 5
-8 - 24 - 2 - 5 = -39

b. X-3 <------ See * above

f(x)= x³ - 6x² + x-5
f(3)³ - 6(3)² + (3) - 5 <------ No, this should be "f(3) = (3)³ - 6(3)² + (3) - 5."

27-54+3-5= -29

I believe this should be correct now sir?

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