Relations - transitive

punchline

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Hi, iv learnt about relations and how they can be reflexive, symetric or transitive

im unsure of how to prove if a relation is or isnt each of these, can a relation be more than one of these? can it be all of them?

Bellow is a question where iv been asked to identify if each of these relations is reflexive, symetric or transitive and give a reason why.

In the real numbers x~y if 3x+5y is not rational

also, in the intiger numbers x~y if 3x+5y is divisible by 8

and help would be awesome, thanks
 
Hi, iv learnt about relations and how they can be reflexive, symetric or transitive

im unsure of how to prove if a relation is or isnt each of these, can a relation be more than one of these? can it be all of them?

Bellow is a question where iv been asked to identify if each of these relations is reflexive, symetric or transitive and give a reason why.

In the real numbers x~y if 3x+5y is not rational

also, in the intiger numbers x~y if 3x+5y is divisible by 8

and help would be awesome, thanks
equality, =, has all three properties as for x, y and z in the reals we have x=x for all reals, if x=y then y=x and if x=y and y=z then x=z.

Suppose 3x+5y is not rational, that is x~y. The question is whether or not 3y+5x is not rational. If it is not rational then ~ has the symmetric property.

Show us your work for the one above and we will go from there.
 
my attempts

i dont even know where to start if im honest, should i be using algebra to show they are divisable by 8 or should i use number examples?

also if 3x+5y=8k and 3y+5z=8l does that mean that 3x+5z=(3x+5y)+(3y+5z)=8(l+k) ?
 
Hi, iv learnt about relations and how they can be reflexive, symetric or transitive
im unsure of how to prove if a relation is or isnt each of these, can a relation be more than one of these? can it be all of them? Bellow is a question where iv been asked to identify if each of these relations is reflexive, symetric or transitive and give a reason why.
In the real numbers x~y if 3x+5y is not rational
Please try to write your postings in somewhat standard English.

Suppose \(\displaystyle x=\dfrac{\sqrt2}{3}~\&~y=\dfrac{-\sqrt2}{5}\) then \(\displaystyle 3x+5y\) is rational but \(\displaystyle 3y+5x\) is irrational. Can that relation be symmetric?
 
Sorry for my poor english.

Thank you for the help!

What im struggling to understand at the moment is:

do all variations of x,y and z need to satisfy the relation?

also if you add in z for the transitive quality, can that also be any intiger if x and y are intigers?

cheers for the help again! really struggling with this topic
 
hi im in desperate need of help on this topic, i have class test tomorrow and i cant even figure out the answer to these simple questions. Cheers
 
Hi! I've learned about relations, and about how they can be reflexive, symmetric, or transitive.

I'm unsure of how to prove if a given relation is or is not each of these. Can a relation be more than one of these? Can it be all of them?

Below is a question where I have been asked to identify if each of these relations is reflexive, symmetric, or transitive, and to give a reason why:

1. In the real numbers, x~y if 3x+5y is not rational.

2. In the integers, x~y if 3x+5y is divisible by 8
What is your book's specific definitions of "reflexive", "symmetric", and "transitive"? In mathematics, definitions are everything, so you'll need to be certain and clear on these definitions. (You can review many articles with definitions and worked examples here. For instance, the definitions with worked examples [both "yes, it is" and "no, it isn't"] may be found here.)

Looking at the first relation, we have:

1. Let x and y be real numbers. These numbers x and y are related according to the rule "3x + 5y is not a rational number".

a. To be reflexive, it must be true that, for any real number x, this number is related to itself under the relation "3x + 5x = 8x is not a rational number".

Is this true for all real numbers? Can you find a real number such that 8x is irrational? (Think about multiples of irrational numbers like "pi".) So is this relation reflexive? (Note: Only one counter-example is necessary in order to say "no, it isn't.")

b. To be symmetric, it must be true that, for any x and y such 3x + 5y is irrational, then 3y + 5x is also irrational. Is there a counter-example for this? Or can you prove (in generality) that 3y + 5x must also be irrational?

c. To be transitive, it must be true that, for any x and y such that 3x + 5y is irrational, and for any z such that 3y + 5z is irrational, it is also true that 3x + 5z is irrational. Can you use the fact that the middle variable, the y, is not present in the final "then" part, to create a counter-example?

2. Let x and y be integers. These integers x and y are related according to the rule "3x + 5y is divisible by 8".

a. To be reflexive, it must be true that, for any integer x, 3x + 5x = 8x is divisible by 8. Since the expression is an integral multiple of 8, then this is clearly fulfilled by any integer. So... what can you conclude?

b. To be symmetric, it must be true that, for any integers x and y for which 3x + 5y is a multiple of 8, then 3y + 5x is also a multiple of 8. Does this "feel" right to you, or are your instincts leading you to think that this might not be true? Can you find a pair of integers x and y so that 3x + 5y = 8m for some integer m, but 3y + 5x is not? Can you try fiddling with some numbers and see what you come up with? Or can you prove this to be true, in full generality?

c. To be transitive, it must be true that, for any integers x and y for which 3x + 5y is a multiple of 8, and for any z for which 3y + 5z is a multiple of 8, then it must be that 3x + 5z is a multiple of 8. Does this feel right, or should you maybe try for a counter-example?

If I've missed your point, or if you have other questions, kindly please reply with specifics (as, I'm afraid, "I totally don't get it" is not helpful). Thank you! ;)
 
Thank you very much for the help, that makes a whole load of sence.

For the first one i have created a counter example but im struggling to finish the final proof.

I have said:

3x-z = (3x+5y)-(5y+z) = (a/b)-(b/c) = (ca-b^2)/bc

now if i prove that the final expression is not rational then i have shown that the relation is transitive.

Have I gone down the correct route? or have i made any mistakes, also some help proving that the expression (ca-b^2)/bc is no rational would be really helpful because i dont know where to start
 
b. To be symmetric, it must be true that, for any x and y such 3x + 5y is irrational, then 3y + 5x is also irrational. Is there a counter-example for this? Or can you prove (in generality) that 3y + 5x must also be irrational?


I understand this point but again my knowledge of proofs is lacking, how could i show that 3y+5x is irrational when 3x+5y is irrational

also just to confirm my understanding of symmetric relations, does 3x+5y and 3y+5x have to be irrational for all inputs or does 3y+5x have to be irrational only for x and y which cause 3x+5y to be irrational?

thanks again for the help, saving me stressing my self out quite so much!
 
I understand this point but again my knowledge of proofs is lacking, how could i show that 3y+5x is irrational when 3x+5y is irrational
To show a statement is not true, you must provide a counter-example .
I gave one in #4.
 
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