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The minute hand of a clock is 11 centimeters long, whereas the hour hand is 5 centimeters long. How fast is the distance between the tips of the hands changing at the 2 o'clock position?

Does anyone know how to find this problem?
 
let D = distance between the tips in cm
let a = angle between the hands

using the law of cosines ...

D^2 = 11^2 + 5^2 - 2(11)(5)cos(a)

take the derivative of the above equation w/r to time, t ...

2D(dD/dt) = 110sin(a)*(da/dt)

dD/dt = 110sin(a)*(da/dt)/(2D)

now, at 2 o'clock ...

a = 1/6 of the clock circle = pi/3 radians

rate of change of the minute hand's angle = 2pi radians in 60 minutes =
(pi/30) rad/min
rate of change of the hour hand's angle = 2pi radians in 12 hours =
(pi/6)rad/hr = (pi/360) rad/min

so, at 2 o'clock, da/dt = (pi/30) rad/min - (pi/360) rad/min = (11pi/360) rad/min

also, at 2 o'clock, D = sqrt[146 - 110cos(pi/3)]

punching all this stuff into a calculator yields ...
dD/dt = approx 0.4793 cm/min
 
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