Water is leaking out of an inverted conical tank at a rate of 12500 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate at which water is being pumped into the tank.
I know that the volume at a given height would be:
(pi/27) * h^2 and that the problem gives dh/dt as 20 cm/min when height = 200 cm
However I am not exactly sure how to form the rest of the equation to find the rate. Any help appreciated.
I know that the volume at a given height would be:
(pi/27) * h^2 and that the problem gives dh/dt as 20 cm/min when height = 200 cm
However I am not exactly sure how to form the rest of the equation to find the rate. Any help appreciated.