According to Charles' Law, if the pressure of a dry gas remains constant while it is being compressed, the temperature, T, in degrees Celsius, and the volume, V, in cubic centemeters, satisfy the equation V/T = C, where C is a constant.
At a certain time, the volume is 400 cm^3 and the temperature is 20 degrees Celsius. If, at the same time, the temperature is increasing at a rate of 0.5 degrees-C/min, determine the rate of change of the volume.
V = 400
T = 20
C =
dv/dt = ?
dT/dt = 0.5
dc/dt =0
d/dt V / (d/dt T) = d/dt C
d/dt 400 = 10
d/dt = 10/400 = 0.025
Could someone please check this over? Thank you!
______________________________________________
Edited by stapel -- Reason for edit: spelling, punctuation, capitalization, etc
At a certain time, the volume is 400 cm^3 and the temperature is 20 degrees Celsius. If, at the same time, the temperature is increasing at a rate of 0.5 degrees-C/min, determine the rate of change of the volume.
V = 400
T = 20
C =
dv/dt = ?
dT/dt = 0.5
dc/dt =0
d/dt V / (d/dt T) = d/dt C
d/dt 400 = 10
d/dt = 10/400 = 0.025
Could someone please check this over? Thank you!
______________________________________________
Edited by stapel -- Reason for edit: spelling, punctuation, capitalization, etc
