related rates: A spotlight on the ground shines on a wall

sickplaya

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A spotlight on the ground shines on a wall 12m away. If a man 2m tall walks from the spotlight toward the building at a speed of 1.6m/s, how fast is the length of his shadow on the building decreasing when he is 4m from the building?
 
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Let x(t) be the distance from the spotlight to the man at time t. Suppose t=0 when he's right near the light. Let h(t) denote the height of his shadow.

We know dx/dt = 1.6, we want dh/dt when x=4.

Draw a picture and use similar triangles to see that x/12 = 2/h at any t.

Then h(t) = 24/x(t). Differentiate, using chain rule.
 
ok i get your answer (-2.4m/s) if the question is 4m from the spotlight but the question is 4m from the building i dunno im still not sure where i went wrong; i got your similar triangle properties
 
sickplaya said:
... but the question is 4m from the building

My bad! You're right, -0.6 m/s in that case because you need dh/dt when x=12-4=8.
 
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