Related Rate

durhamre

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Feb 25, 2010
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Water is being collected from a block of ice with a square base. The water is produced because the ice is melting in such a way that each edge of the block is decreasing in length at 2in/hr, while the height of the block is decreasing at 3in/hr. What is the rate of the flow of water into the collecting basin when the base has an edge length of 3ft, and the block is 3ft tall? (You may assume that water and ice have the same density).
 
Water is being collected from a block of ice with a square base. The water is produced because the ice is melting in such a way that each edge of the block is decreasing in length at 2in/hr, while the height of the block is decreasing at 3in/hr. What is the rate of the flow of water into the collecting basin when the base has an edge length of 3ft, and the block is 3ft tall? (You may assume that water and ice have the same density).

What have you tried so far???

Let s be a base length. At the point in question, s = 3. Since the base edges are decreasing at 2 in/hr, ds/dt = -2.

Let h be the height. At the point in question, h = 3. Since the height is decreasing at 3 in/hr, dh/dt = -3.

V = hs^2

This is a related rates problem, so you always want to differentiate with respect to time.

Your turn.
 
So I know where I went wrong now...I didn't make the rates negative. Thank you!:D
 
I didn't make the rates negative.

I should point out that the dV/dt for the cube will be negative, but the flow of water into the collecting basin is equal to and opposite of that.
 
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