Region Bounded

[dannatyler]

The question is:
The region bounded by y=sinx y=0,x=0 and x=pi is revolved around the x-axis. find the volume of the solid generated.
Here is what I came up with:
pi integral from 0 to pi (sinx)^2 dx = pi integral from 0 to pi 1/2 (1-cos2x) dx = pi/2(x-(sin2x/2)= pi^2/2
Is that the right answer???

 

[galactus]

Lookin' good

Now, try it with shells and see if you get the same solution.

Here is an animated graph of your function.

 

[dannatyler]

That's so cool. Its hard to visualize what they are talking about.
Thanks for your help.