Reference Angle Theorem

[lewch45]

One other question:

I need to use the Reference Angle Theorem to find the exact value of tan (- pi/3).

 

[stapel]

Assuming that the theorem mentioned in this thread uses the definition I proposed in the other thread, you need to find the reference angle, in radians, that corresponds to -pi/3. That is, you need the angle, between 0 radians and 2pi radians, whose terminal (ending) side is the same as for -pi/3. Then take the tangent of that angle.

As with the other thread, if any part of my assumptions as to your meanings, definitions, and theorems is incorrect, please reply with corrections and clarification. Thank you.

Eliz.

 

[lewch45]

Ok....here's what I have so far:

The reference angle for -pi/3 = 5 pi/3

Is that correct?

Then I would take the tangent of that angle??

Could someone please let me know if I'm headed in the right direction? Any help would be appreciated.

 

[pka]

I would say that the reference angle of \(\displaystyle \frac{{ - \pi }}{3}\) is \(\displaystyle \frac{\pi }{3}\).

Therefore: \(\displaystyle \L
\tan \left( {\frac{{ - \pi }}{3}} \right) = - \tan \left( {\frac{\pi }{3}} \right)\)