Can anyone reduce? x^1/3(-8/3x^1/3) - (2-2x^4/3)(1/3x^-2/3) all divided by (x^1/3)^2
J joey123 New member Joined Oct 23, 2005 Messages 29 Nov 5, 2005 #1 Can anyone reduce? x^1/3(-8/3x^1/3) - (2-2x^4/3)(1/3x^-2/3) all divided by (x^1/3)^2
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Nov 5, 2005 #2 Your formatting is ambiguous. Are the exponents all fractions? Does, for instance, "1/3x^-2/3" mean: . . . . .1(3x)(−23)\displaystyle \large{\frac{1}{(3x)^{(-\frac{2}{3})}}}(3x)(−32)1 ...or: . . . . .13x−23\displaystyle \large{\frac{\frac{1}{3}x^{-2}}{3}}331x−2 ...or something else? Please reply with clarification. Thank you. Eliz.
Your formatting is ambiguous. Are the exponents all fractions? Does, for instance, "1/3x^-2/3" mean: . . . . .1(3x)(−23)\displaystyle \large{\frac{1}{(3x)^{(-\frac{2}{3})}}}(3x)(−32)1 ...or: . . . . .13x−23\displaystyle \large{\frac{\frac{1}{3}x^{-2}}{3}}331x−2 ...or something else? Please reply with clarification. Thank you. Eliz.
