reducing algebraic fractions

alaska33355

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Mar 4, 2010
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Our problem is x +8, all over 2 in the denominator....divided by 3x +24, all over 5 in the denominator.
Can we reduce the 8 over the 2 to 4? Then we tried multiplying by the second fraction (it's hard to post fractions!). We should get an answer of 5/6 but haven't gotten that.

Thanks for any help!
 
alaska33355 said:
Can we reduce the 8 over the 2 to 4?
NO!

HINT:
[(x + 8) / 2] / [(3x + 24) / 5]

= [(x + 8) / 2] * [5 / (3x + 24)]

= [(x + 8) / 2] * [5 / (3(x + 8))]

If that's not enough, you need classtoom help...
 
Thanks, Denis......we had gotten that far, but this is where we are stuck. Can this be reduced further?
 
alaska33355 said:
Thanks, Denis......we had gotten that far, but this is where we are stuck. Can this be reduced further?

Hi alaska33355,

\(\displaystyle \frac{x+8}{2} \div \frac{3x+24}{5}\)

\(\displaystyle \frac{x+8}{2} \cdot \frac{5}{3(x+8)}\)

\(\displaystyle \frac{5(x+8)}{6(x+8)}\)

The two (x + 8)s cancels out.

 
alaska33355 said:
we had gotten that far, but this is where we are stuck

And the reason for not sharing this information up-front is?

(a) It was a secret

(b) It was too much to type

(c) We expect others to read our mind

(d) We don't read posts with titles like "Read Before Posting"

:p

In the future, try to remember that the more specific you are about your situation, the better the responses you will get back.
 
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