red/king (e16q21) *

T

tamiatha

Junior Member
Joined
Apr 26, 2009
Messages
109
2 cards are drawn from a standard deck of cards.
Find the probability that a king or red card is drawn.

P=a king or a red card
1-P=no king and no red
=1-24C21/52C2
=1-24*23/(52*51)
=1-0.7919 or 79.19%
P-175/221

correct?
 
Re: red/king (e16q21)

tamiatha said:
2 cards are drawn from a standard deck of cards.
Find the probability that a king or red card is drawn.

P=a king or a red card
1-P=no king and no red
=1-24C21/52C2
=1-24*23/(52*51) = 1- 0.208144796 = 0.791855204


=1-0.7919 or 79.19% <<<< What are you doing here?
P-175/221<<<< What are you doing here?

correct? ---- sort of
Click to expand...
edited
 
Re: red/king (e16q21)

Hello, tamiatha!

We can solve the problem head-on . . .

Two cards are drawn from a standard deck of cards.
Find the probability that a King or Red card is drawn.
Click to expand...

\(\displaystyle \text{Formula: }\;P(\text{King} \vee \text{Red}) \;=\;\underbrace{P(\text{King})}_{\frac{4}{52}} + \underbrace{P(\text{Red})}_{\frac{26}{52}} - \underbrace{P(\text{King} \wedge \text{Red})}_{\frac{2}{52}}\)

. . . . . . . . . . . . . . . . . .\(\displaystyle = \;\frac{4}{52} + \frac{26}{52} - \frac{2}{52} \;\;=\;\;\frac{28}{52} \;\:=\;\:\frac{7}{13}\)

 
Re: red/king (e16q21)

tamiatha said:
2 cards are drawn from a standard deck of cards.
Find the probability that a king or red card is drawn.
P=a king or a red card
1-P=no king and no red, P-175/221. correct?
Click to expand...
Yes that is correct.
\(\displaystyle 1 - \frac{^{24}\mathcal{C}_2}{^{52}\mathcal{C}_2}\)
 
Re: red/king (e16q21)

I see Soroban still cheats at cards :shock:
 
Re: red/king (e16q21)

so who is correct

note to soroban:
i REALLY like the guys that "do" homework :D
 
You must log in or register to reply here.
Top