2L+2W=24
L+W=12
area=LW
area=L[12-L]
area=12L-L^2
this will help you visualize the problem, plot on rectangular coordinates, W along the y axis and L along the x axis, with L from 0 to 12. The curve rises as L increases and then returns to 0 as L goes to 12
d[area]/dL=12-2L set d[area]/dL=0
0=12-2L
L=6 answer
Arthur
0=L dW/dL+W