reciprocal with imaginary part

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mathgeek

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Sep 22, 2009
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The problem states to find the reciprocal of (2/13)-(3/13)(i) in x+yi form where x and y are real numbers.
I simplified it to (2-3i)/13.
Then I found the reciprocal which was 13/(2-3i)
I was wondering how to put 13/(2-3i) into x+yi form. I can figure it out on my calculator, but I would like to know how to do it by hand
 
mathgeek said:
The problem states to find the reciprocal of (2/13)-(3/13)(i) in x+yi form where x and y are real numbers.
I simplified it to (2-3i)/13.
Then I found the reciprocal which was 13/(2-3i)
I was wondering how to put 13/(2-3i) into x+yi form. I can figure it out on my calculator, but I would like to know how to do it by hand
Click to expand...

Multiply the numerator and the denominator by the conjugate of (2-3i).
 
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