Rearrange in terms of x

mikexz

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Joined
Feb 21, 2006
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Rearrange in terms of y: x^3 +y^3 = 0


My attempt:

x^3 = -y^3
? there's nothing I can do now since I can't take the square root of a negative number???

-solutions at the back says it's x=-y but that doesn't make sense
help?
 
mikexz said:
Rearrange in terms of y: x^3 +y^3 = 0


My attempt:

x^3 = -y^3
? there's nothing I can do now since I can't take the square root of a negative number???

But you'll take CUBE root of negative number - which would be negative

since

(-y) * (-y) * (-y) = -y^3

then

\(\displaystyle ^3\sqrt{-y^3} \, = -y\)

-solutions at the back says it's x=-y but that doesn't make sense
help?
 
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