Rearrange 1/x+1 = 2sin(x) + 3 four different times

[Megan3]

Please help me rearrange this equation 4 different times, thanks:

1/x+1 = 2sin(x) + 3

 

[ksdhart2]

What does your instructor/textbook/worksheet mean by "rearrange this equation?" For instance, my interpretation suggests that if the original equation was:

3 + x = 7 + y

Then, the following would be four possible "rearrangements:"

x + 3 = 7 + y
3 + x = y + 7
x - 4 = y
x = y + 4

Is the above perhaps something similar to what you're expected to do? The more specific you can be about what the problem is asking, the better our help will be.

 

[Otis]

1/x+1

If x+1 is the denominator, then we need to show that with grouping symbols around the denominator.

In other words, typing 1/(x+1) means \(\displaystyle \dfrac{1}{x+1}\)

But typing 1/x+1 (no grouping symbols) means \(\displaystyle \dfrac{1}{x}+1\)

Cheers :cool: