Joyce said:I know this is my second post but it's my last I promise! (studying for a test).
a)2^2x-9(2^x)+8=0
b) 4^2x-17(4^x)+16=0
I know ur supposed to factor but not sure how.........
Is the first equation meant to be as follows?Joyce said:a)2^2x-9(2^x)+8=0
b) 4^2x-17(4^x)+16=0
You have been given a quadratic in 2<sup>x</sup>. How are you getting these values (above) for the coefficients of 2<sup>2x</sup> and 2<sup>x</sup>?Joyce said:a= 2, b= -18, c= 8
An HTML tag.Joyce said:what is <sub>?
Check your work: (y + 1)(y + 8) does not multiply to y<sup>2</sup> - 9y + 8.Joyce said:2^2x-9(2^x)+8=0
Factor: (2^x+1)(2^x+8)
Should be (2^x - 1)(2^x - 8) = 0Joyce said:2^2x-9(2^x)+8=0
Factor:
(2^x+1)(2^x+8)
So your class hasn't covered how to factor quadratics yet...?Maryanne said:[W]hen you factor something I [know] [you're] supposed to break the equation into two...but how do you know which numbers to use?