real world applications-integrals

tmd1979

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Apr 6, 2010
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16
I am using a postage function, where C(x)= .37 if 0<x<=1, .60 if 1<x<=2, .83 if 2<x<=3, 1.06 if 3<x<=4, and 1.29 if 4<x<=5.

Is this function integrable? Can you explain why or why not?

Can the definite integral, C(x), be calculated over closed intervals that contain the points of discontinuity. Please explain of how this might be done.

One more thing, for example, what would be an integral of C(x) over interval [0.5, 2] and how this would be calculated?

I am thinking [.60(2)-.60(1)] +[.37(1)-.37(.5)]=.6+.185=.785

I don't think I am even close.
 
I am sorry that I posted the same post twice. There is no response to either of them. I really do appreciate the help. Thanks!
 
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