DutifulJaguar9
New member
- Joined
- Jul 4, 2019
- Messages
- 4
This is the question "Prove the following by using: a direct argument with two cases for n; and the properties of even and odd numbers.
[MATH]\forall n\in\mathbb{N}, n^{3}+n+2 [/MATH] is even."
I understand what I need to do to show that this is true. I show that:
If n is odd then n3 is odd, n is odd, 2 is even, then n3+n+2 is even
& If n is even, then n3is even, n is even, 2 is even, n3+n+2 is even
Both because of the properties of even and odd numbers.
However, I don't know how to show that in a formal proof (I also don't think I understand what a direct argument is.
Thanks
[MATH]\forall n\in\mathbb{N}, n^{3}+n+2 [/MATH] is even."
I understand what I need to do to show that this is true. I show that:
If n is odd then n3 is odd, n is odd, 2 is even, then n3+n+2 is even
& If n is even, then n3is even, n is even, 2 is even, n3+n+2 is even
Both because of the properties of even and odd numbers.
However, I don't know how to show that in a formal proof (I also don't think I understand what a direct argument is.
Thanks