Ratios Problem: If x/y = 3 and 1/3, find x - 3y / 2x - 5y
- Thread starter megan0430
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- Feb 4, 2004
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Assuming "3 and 1/3" to be a mixed number (yes, they're hard to write in this format), and assuming the fractional expression to be (x - 3y)/(2x - 5y), what have you tried? How far have you gotten? Where are you stuck?
You've been given worked solutions for quite a few "ratio" exercises so far. Please reply showing full details of how you have worked from what you have been given.
Thank you.
Eliz.
You've been given worked solutions for quite a few "ratio" exercises so far. Please reply showing full details of how you have worked from what you have been given.
Thank you.
Eliz.