Rationalize the denominator

[Guest]

Please help with this one Im lost

7/ square root of [3] - square root of [2]

could you please show the steps on how the answer is solved?

 

[pka]

\(\displaystyle \L
\begin{array}{rcl}
\frac{7}{{\sqrt 3 - \sqrt 2 }} & = & \frac{7}{{\sqrt 3 - \sqrt 2 }}\left(\frac{{\sqrt 3 + \sqrt 2 }}{{\sqrt 3 + \sqrt 2 }}\right) \\
& = & \frac{{7\left( {\sqrt 3 + \sqrt 2 } \right)}}{{\left( {\sqrt 3 } \right)^2 - \left( {\sqrt 2 } \right)^2 }} \\
& = & \frac{{7\left( {\sqrt 3 + \sqrt 2 } \right)}}{{3 - 2}} \\
& = & 7\left( {\sqrt 3 + \sqrt 2 } \right) \\
\end{array}\)

 

[Ted]

[I answered this one and then deleted it because I made a sign error... please disregard any answer from me if you saw it because PKA's is correct.]