Should we assume that grouping symbols have been omitted, and that you really mean "f(x) = (3x)/(x^2 - x - 6)"?
. . . . .\(\displaystyle \displaystyle{f(x)\, =\, \frac{3x}{x^2\, -\, x\, -\, 6}}\)
What did you get when you
plugged zero in for x and solved for y? What did you get when you plugged zero in for y and solved?
When i plugged 0 for x, I got 3x / ( x-3 )( x + 2 ).
and when I plugged 0 for y, I got x is not equal 3 , x is not equal -2 and x is not equal 0 .
What did you get when you
checked the zeroes of the denominator? What did you get when you plugged the degrees into
the formula they gave you?
When I checked the zeros at the denominator, I got for the vertical asymptote, x=3 and x= -2 . And i don`t know how to get the horizontal asymptote.

And I don`t know what do you mean by " what did you get when you plugged the degrees into the formula ? " because my teacher didn`t mention anything about the degrees.
What did you get when you looked at
the graph? (Since you are having trouble with beginning-algebra topics like intercepts, I'm assuming that you haven't gotten to calculus yet.)
I don`t know how to sketch the graph yet

, and you are right, cause I haven`t taken the calculus yet.

, I`m taking Advanced function, chapter 3.
Please reply with a clear listing of your efforts so far, or else with specifications about the lesson instruction you are seeking. Thank you!