rational expressions

[DEA52J23]

I am having difficulty with the following problem. Any help would be appreciated.

3a + 3b/4c * 12/5 (a+b) =

Deanne

 

[Deleted member 4993]

I am having difficulty with the following problem. Any help would be appreciated.

3a + 3b/4c * 12/5 (a+b) =

Deanne

You have not told us what do you need to do?

Exactly where are you stuck?

 

[DEA52J23]

I know I need to factor, but not sure if it is 3(a+b)/4c * 12/5(a+b)

I believe I could cancel out the a+b -then would I reduce 4c & 12 to c & 3 and then multiply across?

 

[mmm4444bot]

I believe I could cancel out the a+b That is correct, assuming the given expression is:

\(\displaystyle \frac{3a \;+\; 3b}{4c} \cdot \frac{12}{5(a + b)}\)



then would I reduce 4c & 12 to c & 3 and then multiply across? Yes, you got it!

Also, when typing algebraic ratios, we need to use grouping symbols to clearly show numerators and denominators.

Like so:

[3a + 3b]/(4c) * 12/[5(a + b)]

3(a + b)/(4c) * 12/[5(a + b)]

3/(4c) * 12/5

3/c * 3/5

Without grouping symbols, typing 3a + 3b/4c means the following.

\(\displaystyle 3a \;+\; \frac{3b}{4} \cdot c\)