rational equation: solve (x + 5)^2/3 = 4

bandaidgirl

New member
Joined
Sep 3, 2006
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13
solve and check with rational exponents

(x + 5)^2/3 = 4

[(x + 5)^2/3]^3/2 = 4^3/2

thats all the further i can get
 
\(\displaystyle \L
\begin{array}{rcl}
\left( {x + 5} \right)^{\frac{2}{3}} & = & 4 \\
\left[ {\left( {x + 5} \right)^{\frac{2}{3}} } \right]^{\frac{3}{2}} & = & \left( 4 \right)^{\frac{3}{2}} \\
\left( {x + 5} \right) & = & 8 \\
\end{array}\)
 
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