Raticle HELLPPP!!
- Thread starter e.boyer
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This:
\(\displaystyle 3\cdot\sqrt[4]{4-x}\;=\;9\)
What was the last problem in this set that you managed to solve? Why is this one harder?
#1 - Notice that 4-x >= 0 or x <= 4, then proceed as you may wish.
Maybe divide by 3?
\(\displaystyle \sqrt[4]{4-x}\;=\;3\)
Since everything is positive, try a fourth power!
\(\displaystyle 4-x = 3^{4}\)
Are we getting anywhere?
\(\displaystyle 3\cdot\sqrt[4]{4-x}\;=\;9\)
What was the last problem in this set that you managed to solve? Why is this one harder?
#1 - Notice that 4-x >= 0 or x <= 4, then proceed as you may wish.
Maybe divide by 3?
\(\displaystyle \sqrt[4]{4-x}\;=\;3\)
Since everything is positive, try a fourth power!
\(\displaystyle 4-x = 3^{4}\)
Are we getting anywhere?
mmm4444bot
Super Moderator
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- Oct 6, 2005
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e.boyer said:Raticle
A popsicle for owls.