Radicals
- Thread starter sistdm78
- Start date
- Joined
- Apr 12, 2005
- Messages
- 11,339
You have a factor with one term and another factor with two terms. Unless the terms can be combined in the two-term factors, ir is quite unlikelt that a single term will be the result of the multiplication.
\(\displaystyle \sqrt{6} \cdot (-5\sqrt{6}+2) = \left(-5(\sqrt{6})^{2}+2\sqrt{6}\right)\)
This should be familiar. You may know it as something like "The Distributive Property of Multiplication over Addition". Maybe something shorter.
Now what?
\(\displaystyle \sqrt{6} \cdot (-5\sqrt{6}+2) = \left(-5(\sqrt{6})^{2}+2\sqrt{6}\right)\)
This should be familiar. You may know it as something like "The Distributive Property of Multiplication over Addition". Maybe something shorter.
Now what?