Radicals: multiply sqrt of 3 (4 sqrt of 6 - 2 sqrt of 3)

drlandry22

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Mar 31, 2009
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Ok. I have worked this problem 2 times now and I cannot seem to get the answer in the back of the book. I don't know what I am doing wrong.

Instructions: Multiply as indicated. If possible, simplify any radical expression that appear in the product.

Question: The square root of 3 ( 4 square root of 6 - 2 square root of 3)

Sorry for all the words. I hope you get what the problem is. I don't know how to put in the radical sign.
 
Re: Radicals

\(\displaystyle \sqrt{3}(4\sqrt{6}-2\sqrt{3}) = 4\sqrt{18}-2(\sqrt{3})^2=4\sqrt{9 \times 2}-2\times 3 = ...\)
 
drlandry22 said:
I don't know what I am doing wrong.
Unfortunately, we cannot help find errors in working that we cannot see. :oops: In future, please show what you've tried.

drlandry22 said:
I don't know how to put in the radical sign.
To learn how to format math as text, please review this article. Thank you! :D
 
drlandry22 said:
Question: The square root of 3 ( 4 square root of 6 - 2 square root of 3)
I don't know how to put in the radical sign.

If you're as lazy as I am (learn exotic posting!), go like this:

sqrt(3)[4sqrt(6) - 2sqrt(3)]
 
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