y - (4y^1/2) - 5 = 0 i need to solve for y i know that y=25 but how does one get that answer?
D danpittack New member Joined Aug 22, 2005 Messages 1 Aug 22, 2005 #1 y - (4y^1/2) - 5 = 0 i need to solve for y i know that y=25 but how does one get that answer?
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Aug 22, 2005 #2 y - 4y^1/2 - 5 = 0 Wince you didn't tell us what you have tried, I get to pick on you a little. :wink: Hmmm... What do you know about the quadratic formula? Could you do it if it were: x^2 - 4*x - 5 = 0?
y - 4y^1/2 - 5 = 0 Wince you didn't tell us what you have tried, I get to pick on you a little. :wink: Hmmm... What do you know about the quadratic formula? Could you do it if it were: x^2 - 4*x - 5 = 0?