Radian measure

jinx24

New member
Joined
Jan 23, 2006
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Hi all! I need a little help with this problem.

"Two angles in a triangle have radian measure pi/5 and pi/6. What is the radian measure of the third angle."

I know that the "radian measure" is the arc length / radius. But that does not really get me anywhere.

I don't know where to start. The only thing that I have done is convert the two radians into degrees, but I didn't get anywhere with that.

Thank you.
Jenny
 
What is the angle-sum of any triangle?

Eliz.
 
Thank you. I guess I was on the right track by converting into degrees.
 
Hello, Jenny!

You're making hard work out of a simple problem.
\(\displaystyle \;\;\)And you don't have to convert to degrees.

Two angles in a triangle have radian measure \(\displaystyle \frac{\pi}{5}\) and \(\displaystyle \frac{\pi}{6}\).
What is the radian measure of the third angle.
We know that the sum of the angles of a triangle is: \(\displaystyle 180^o\) or \(\displaystyle \pi\) radians.

If two of the angles are \(\displaystyle \frac{\pi}{5}\) and \(\displaystyle \frac{\pi}{6}\),
\(\displaystyle \;\;\)the third angle is: \(\displaystyle \,\pi\,-\,\frac{\pi}{5}\,-\,\frac{\pi}{6}\;=\;\left(1\,-\,\frac{1}{5}\,-\,\frac{1}{6}\right)\pi\;=\;\frac{19\pi}{30}\) radians.
 
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