Quick Question

[JANGurTHANG247]

So I have a calculus question and not sure which method to use

it says...

y= x^1/2, y=2 x=0

Find the volume as this is rotating around y=2, I got the answer 8pi/3 but I'm not sure how? lolz but can someone please show me how to set this up as a dy integral?

 

[lookagain]

So I have a calculus question and not sure which method to use

it says...

y= \(\displaystyle > > > \)x^1/2 \(\displaystyle < < < \), y=2 x=0

Find the volume as this is rotating around y=2, I got the answer 8pi/3 but I'm not sure how? lolz but can someone please show me how to set this up as a dy integral?

That should be y = x^(1/2) or \(\displaystyle y = x^{\frac{1}{2}}.\)

 

[tkhunny]

Perhaps you achieved this result by looking in the back of the book?

\(\displaystyle \pi\int_{0}^{4}(2-\sqrt{x})^{2}\;dx\)

You do the other one.