We have: log(1785)+log(2521)=log(5)+log(5)=2⋅log(5)=log(52)=log(25)log(85)−log(17)+0.5log(25)
It's already solved for x . . .Solve for x:x=4⋅log(2)+log(3)
log x= 4 log2 +log3.
Yes, I certainly did! . . . *blush*wjm11 said:Soroban has already solved it for you, although I think he misread "log x" as being just x in the problem statement.
No. When Soroban replied, the equation read "x=". WTF? was editing the question while Soroban was typing up his reply, changing the equation to "log(x)".wjm11 said:Soroban...misread "log x" as being just x...
I'm sorry, but I must be missing the connection. How did you get "6<sup>n-5</sup>" from "log(x) = 4 log(2) + log(3)"?WTF? said:I'm in need of another push.
6^(n-5) = 400
You had: (n−5)log(6)=log(400)Hello, I'm in need of another push.
6n−5=400
Hm, don't know how to solve for n.
I tried setting it up as: (n−5)log6=log400 ... but no luck.
. . . Really? This should have worked!
Please post new questions as new threads, rather than as replies to old threads, where they tend to be overlooked.WTF? said:I have another one...
Posting separate questions as separate posts is not "spam". Posting ads is spam.WTF? said:Would this not be spam?