Sweet, I got it now.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 May 5, 2006 #2 Let \(\displaystyle \L\\u=ln(x)\). Therefore, \(\displaystyle \L\\du=\frac{dx}{x}\) See it now?. It's not as complicated as it looks.
Let \(\displaystyle \L\\u=ln(x)\). Therefore, \(\displaystyle \L\\du=\frac{dx}{x}\) See it now?. It's not as complicated as it looks.
