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Quick question about related rates.
- Thread starter Dave J
- Start date
Saying "Y is decreasing at a rate of -2" is equivilant of saying "Y is increasing at a rate of 2." Omitting the fact that you had a double negative, it is still unclear to me what you mean.
It is correct (in my tiny mind, at least) to say "Y is decreasing twice as fast as x is increasing."
It is correct (in my tiny mind, at least) to say "Y is decreasing twice as fast as x is increasing."
Yes, i know:Dave J said:well i mean y` as dy/dx
\(\displaystyle \L \frac{dy}{dx}=-2 \,\, \Rightarrow \,\, dy = -2dx\)
So, as x increases, y is decreasing at twice the "speed" as x is increasing.
Look at your original graph of \(\displaystyle y=-2x \,\, + \,\, whatever\). As x goes up, y goes down by -2*(whatever x went up by).