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im doing simpsons/trapezoidal methods etc. And it says find the area below the curve f(x)= x^3-2x
That just means integral (x^3-2x)dx right?
That just means integral (x^3-2x)dx right?
The answer really depends on the interval. Area is found by integrals of non-negative functions. From sqrt(2) on this function is positive. So yes, on say [2,5] use Simpsons/trapezoidal methods to find area. But on say [0,5] care must be taken.aswimmer113 said:im doing simpsons/trapezoidal methods etc. And it says find the area below the curve f(x)= x^3-2x. That just means integral (x^3-2x)dx right?
No, that is not correct! It depends upon the interval of integration.aswimmer113 said:so its juts S (x^3-2x)dx, right? I can use the formula i just want to verify this step.