quick derivative question

xtrmk

New member
Joined
Aug 30, 2006
Messages
22
Can someone tell me what i am doing wrong?

Find dy/dx for sinx - cosy - 2 = 0

I got it down to
cosx - (-siny)(dy/dx) = 0
cosx + siny(dy/dx)
dy/dx = -(cosx) / (siny)

however the answer choices don't match but i am guessing its cot something. the answers are a) -cotx b)-coty c) cosx/siny d) -cscy cosx e) (2-cosx)/siny

help is appreciated, thanks!
 
review your basic trig identities ...

(-cosx)/(siny) = -(1/siny)(cosx) = (-cscy)(cosx)
 
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