Quick check of my answer

Handicap Joe

New member
Joined
Aug 20, 2009
Messages
6
Simplify by taking roots of the numerator and the denominator. Assume that all expressions under radicals represent positive numbers.

?((8x^11)/y^3 )

I took the cube root of 8x^11 and got 2x^11?
I took the cube root of y^3 and got y?
Therefore I ended up with

(2x^11)/y

How'd I do? I feel confident about the y but not the 2x^11?
 
Handicap Joe said:
Simplify by taking roots of the numerator and the denominator. Assume that all expressions under radicals represent positive numbers.

?((8x^11)/y^3 )

I took the cube root of 8x^11 and got 2x^11?

That is not correct

\(\displaystyle ^3\sqrt{\frac{8 \cdot x^{11}}{y^3}} \, = \, ^3\sqrt{\frac{2^3 \cdot x^9 \cdot x^2}{y^3}} \, = \,\frac{2\cdot x^3}{y}\cdot ^3\sqrt{x^2}\)


I took the cube root of y^3 and got y?
Therefore I ended up with

(2x^11)/y

How'd I do? I feel confident about the y but not the 2x^11?
 
Top