question

[orir]

i need to find an m (m>0)
so
for every x>m we get that

(x²-2x)/(x+2cosx) > 1000

 

[Bob Brown MSEE]

i need to find an m (m>0)
so
for every x>m we get that

(x²-2x)/(x+2cosx) > 1000

(x²-2x)/(x+2cosx)~ x-2 for large x

I'd say any m> ~1003 would work
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No requirement to find the smallest m, so m=1000000000 is for sure ok