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speed4baseball

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ok so im doing a problem for solving formulas which is

A=1/2d_1d_2 and i am solving for d_1
*by the way _ is an underscore represented as a diminished # as opposed to an exponent

so my answer was d_1=A-1/2d_2
^ is this correct?
 
speed4baseball said:
ok so im doing a problem for solving formulas which is

A=1/2d_1d_2 and i am solving for d_1
*by the way _ is an underscore represented as a diminished # as opposed to an exponent

so my answer was d_1=A-1/2d_2
^ is this correct?
Click to expand...

I THINK that this is what you mean:

A = (1/2)*d[sub:2ne1fd9r]1[/sub:2ne1fd9r]*d[sub:2ne1fd9r]2[/sub:2ne1fd9r]

It's often necessary to use parentheses to indicate CLEARLY what belongs in the denominator of a fraction. In this case, d[sub:2ne1fd9r]1[/sub:2ne1fd9r] and d[sub:2ne1fd9r]2[/sub:2ne1fd9r] are not in the denominator of the fraction.

Ok...you want to solve for d[sub:2ne1fd9r]1[/sub:2ne1fd9r]. I'd start by multiplying both sides of the equation by 2 (to eliminate the fraction):

2*A = 2*(1/2)*d[sub:2ne1fd9r]1[/sub:2ne1fd9r]*d[sub:2ne1fd9r]2[/sub:2ne1fd9r]

2A = d[sub:2ne1fd9r]1[/sub:2ne1fd9r]*d[sub:2ne1fd9r]2[/sub:2ne1fd9r]

Can you take it from here?
 
i understand but since d_1 is not isolated i dont know what to do after if i divide i wont cancel anything out to get d_1 isolated
 
speed4baseball said:
i understand but since d_1 is not isolated i dont know what to do after if i divide i wont cancel anything out to get d_1 isolated
Click to expand...

How would you isolate 'y' in:

4 * y = 20
 
speed4baseball said:
if i divide i wont cancel anything That depends upon the divisor.
Click to expand...

Why don't you show any work?

Am I supposed to guess what you're doing?

For example, if you divide d[sub:1e3552kl]2[/sub:1e3552kl] by d[sub:1e3552kl]2[/sub:1e3552kl], there most certainly is a cancellation.
 
speed4baseball said:
the idea is to solve for d_1 not A
Click to expand...

Yes, I understand that.

I got you to this point:

2A = d[sub:3q1wuxtb]1[/sub:3q1wuxtb]*d[sub:3q1wuxtb]2[/sub:3q1wuxtb]

To isolate d[sub:3q1wuxtb]1[/sub:3q1wuxtb] (to get that by itself), you need to UNDO the multiplication on the right side, where d[sub:3q1wuxtb]1[/sub:3q1wuxtb] is multiplied by d[sub:3q1wuxtb]2[/sub:3q1wuxtb]. The operation that "undoes" multiplication is division. Try dividing both sides of the above equation by d[sub:3q1wuxtb]2[/sub:3q1wuxtb].
 
speed4baseball said:
ok 2A=d_1d_2
so by dividing by d_2
the answer would be d_1 = 2A/d_2 <<<< Correct
^correct? hopefully
Click to expand...
 
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