So I am following the video located here: https://www.khanacademy.org/math/mu...-derivatives/v/partial-derivatives-and-graphs
Given the following multi-variable equation f(x,y) = x^2(y) + sin(y)
The derivative with respect to x = 2xy
And, the derivative with respect to y = x^2 + cos(y)
My question is after I figure out the instantaneous slope at a certain point, lets say (1,-1) as in the video. When evaluating the derivative with respect to x at the point 1,-1, you get -2.
So with that, how do I plot a tangent line that passes through that point on a graph with that specific slope (-2)? And am I correct in thinking that there are *two* tangent lines in a multi-variable function, one for x and one for y?
Given the following multi-variable equation f(x,y) = x^2(y) + sin(y)
The derivative with respect to x = 2xy
And, the derivative with respect to y = x^2 + cos(y)
My question is after I figure out the instantaneous slope at a certain point, lets say (1,-1) as in the video. When evaluating the derivative with respect to x at the point 1,-1, you get -2.
So with that, how do I plot a tangent line that passes through that point on a graph with that specific slope (-2)? And am I correct in thinking that there are *two* tangent lines in a multi-variable function, one for x and one for y?