Question regarding speed and drive time

jrminor

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Jul 17, 2012
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Hello - I spend a bit of time behind the wheel of my car travelling and was hoping for a little assistance (hopefully an equation) regarding the following question:

When a vehicle is exceeding the posted speed limit of 55 mph, 60, 70, 75, etc, in increments of 10 mph, how long must the vehicle remain at that increased speed to actually reduce the overall drive-time by 1 min, 2 mins, etc?

By observing my GPS, I can obviously see that exceeding the speed limit over a period of time causes the GPS unit to gradually reduce the estimated time it will take me to arrive at my destination. I assume it is using what it thinks is the posted speed limit and calculates accordingly. Simply put, when I go faster, the GPS uses this increased speed and translates it into an improved arrival time.

Thank You for the assist!

~ J
 
Hello - I spend a bit of time behind the wheel of my car travelling and was hoping for a little assistance (hopefully an equation) regarding the following question:

When a vehicle is exceeding the posted speed limit of 55 mph, 60, 70, 75, etc, in increments of 10 mph, how long must the vehicle remain at that increased speed to actually reduce the overall drive-time by 1 min, 2 mins, etc?

By observing my GPS, I can obviously see that exceeding the speed limit over a period of time causes the GPS unit to gradually reduce the estimated time it will take me to arrive at my destination. I assume it is using what it thinks is the posted speed limit and calculates accordingly. Simply put, when I go faster, the GPS uses this increased speed and translates it into an improved arrival time.

Thank You for the assist!

~ J

That depends on the distance.

Suppose you have to travel 90 miles.

At 30 mph you would take 3 hrs.

At 45 mph you would take 2 hrs. - saving of 1 hr.

At 60 mph you would take 1½ hrs. - saving of 1½ hr.

At 75 mph you would take 1.2 hrs. - saving of 1.8 hr.

Now suppose you have to travel 180 miles.

At 30 mph you would take 6 hrs.

At 45 mph you would take 4 hrs. - saving of 2 hr.

At 60 mph you would take 3 hrs. - saving of 3 hr.

At 75 mph you would take 2.4 hrs. - saving of 3.6 hr.

The guiding equation is:

distance = speed * time → time = distance/speed
 
Hello - I spend a bit of time behind the wheel of my car travelling and was hoping for a little assistance (hopefully an equation) regarding the following question:

When a vehicle is exceeding the posted speed limit of 55 mph, 60, 70, 75, etc, in increments of 10 mph, how long must the vehicle remain at that increased speed to actually reduce the overall drive-time by 1 min, 2 mins, etc?

By observing my GPS, I can obviously see that exceeding the speed limit over a period of time causes the GPS unit to gradually reduce the estimated time it will take me to arrive at my destination. I assume it is using what it thinks is the posted speed limit and calculates accordingly. Simply put, when I go faster, the GPS uses this increased speed and translates it into an improved arrival time.

Thank You for the assist!

~ J

I'm not sure that I understand your problem correctly - the question is written a little bit vague - but here we go:

1. You want to travel an overall distance of d at a velocity v. Then the travelling time is \(\displaystyle \displaystyle{t=\frac dv}\)

2. I assume that you want to ride a part of d, I label it x, at an increased velocity (v + s) that means s is the additional speed. Then the travelling time decreases by m (normally measured in hours, but you easily can convert hours in minutes)

3. You'll get:

\(\displaystyle \displaystyle{\frac{d-x}{v}+\frac{x}{v+s}=t-m}\)

4. Your GPS only calculates the traveling time corresponding to the new (higher) speed and the distance still to go.
 
When a vehicle is exceeding the posted speed limit of 55 mph, 60, 70, 75, etc, in increments of 10 mph, how long must the vehicle remain at that increased speed to actually reduce the overall drive-time by 1 min, 2 mins, etc?

Are you thinking about some formula -- into which you would plug the total distance, speed limit, the number of 10-mph increases, and the number of minutes by which you would like to decrease the total trip time -- to calculate the number of minutes that you must at drive the increased speed?

Determining such a formula will take some effort; I would first need to know whether this endeavor is frivolous. What motivates your inquiry?

PS: Your GPS gizmo trilateralizes your exact location thousands of times per second using the four (out of 24) satellites in orbital position to accomodate you. Information moves back and forth between you and these satellites at the speed of light. The gizmo knows nothing about speed limits. The gizmo itself calculates your speed based on how far you've moved since the last time it fixed your location. The gizmo's reported information about things like current speed and remaining trip time are generated entirely by software and map-database data within the gizmo.



Here's some more preliminary info.

As your desire is to decrease the total trip time by mere minutes, you should first convert all of your speeds from miles per hour to miles per minute.

EG:

There are 60 minutes in 1 hour

55 miles per hour split into 60 equal pieces yields the equivalent speed of 11/12ths of a mile per minute.

55/60 = 11/12

Distance traveled is the product of constant speed and elapsed time.

d = r*t

Converting 10 miles per hour, we get 1/6 mile per minute.

Hence, your slower speed is r and your faster speed is r + n*1/6 (where n = the number of 10-mph increases).

Now, if you drive at speed r for a total of t minutes AND you drive at speed r + n/6 for a total of T minutes, then the entire distance may be modeled by:

d = r*t + (r + n/6)*T

You seem to be interested in knowing the value of T from given values for d, r, and n.

A formula may be derived by using some algebraic relationships. (We could also break the trip distance into two segments -- one for each speed.)

d = d1 + d2

d1 = r*t

d2 = (r + n/6)*T

With some substitutions and manipulations, we might get an equation looking something like the following that may be solved for T.

t + T - x = d1/r + (d - d1)/(r + n/6)

where x represents the number of minutes by which you desire to reduce the trip time.

Of course, if we were to have a single scenario, things would become much simpler.

EG: you know that your trip distance is 121 miles; you know that the speed limit is 55 mph; you know that you're only willing to increase that speed by one 10-mph increment; and you know that you want to arrive at your destination one minute earlier.

d = 121

r = 55

n = 1

x = 1

These relationships immediately lead to this system of two equations:

11/12*t1 + 13/12*t2 = 121

t1 + t2 = 131

The solution to this system tells us that you must drive at 65 mph for a total of 5.5 minutes, with the remaining 125.5 minutes being driven at 55 mph.

Cheers 8-)
 
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