If
(sin (x))/x = f(x), and that when x = 0, f(x) = 1
Solve, to the nearest decimal point:
∫(from 0 to x) ((sin (t))/t) dt = 1
I tried calculating that using my graphic calculator, and it gave me something around x = 1.1.
I am wondering if there is a formal way (like a proof) of working on this problem?
Thanks!
(sin (x))/x = f(x), and that when x = 0, f(x) = 1
Solve, to the nearest decimal point:
∫(from 0 to x) ((sin (t))/t) dt = 1
I tried calculating that using my graphic calculator, and it gave me something around x = 1.1.
I am wondering if there is a formal way (like a proof) of working on this problem?
Thanks!