Question on how to reverse division problem...

[JJTrapani]

Hello there,

I've been trying to figure out how to do this...
Let t0 = 100.
Let B = .001

t1=t0/(1+B*t0)

So, as it turns out, t1 = 90.91.

Ashamed to say this, but does anyone know how I get back to t0 (with knowing t1 = 90.91)?

(This is based off a version of the cooling mechanism from the Simulated Annealing Algorithm).

Thank you!!

 

[Denis]

x = a / (1 + ab)
a = x(1 + ab)
a = x + abx
a - abx = x
a(1 - bx) = x
a = x / (1 - bx)

 

[Deleted member 4993]

x = a / (1 + ab)
a = x(1 + ab)
a = x + abx
a - abx = x
a(1 - bx) = x
a = x / (1 - bx)

or

1/x = (1+ab)/a ........... assuming x and a was not equal to zero

1/x = 1/a + b

1/a = 1/x - b

1/a = (1 - bx)/x

a = x/(1-bx)