Question on Double Angle theroem

grapz

Junior Member
Joined
Jan 13, 2007
Messages
80
Solve for X in domain ( 0, 2 pi)

4 sin x cos x - 1 = 0

so i factor out a 2

2 ( 2 sin x cos x ) -1 = 0

2 ( sin 2x ) - 1 = 0

sin 2x = 1/2

now this is the part where i do not understand.

x is restricted to domain ( 0, 2 pi)

but , it tells me that 2 x is restricted to the domain (0 , 4 pi ).

Can some one explain to me why the domain is doubled? I mean i can see that its 2x , so its doubled, but i dont' get the logic behind it.

thanks
 
If sin(2x)=1/2\displaystyle sin(2x) = 1/2 then either 2x=π/6\displaystyle 2x = \pi/6 or 2x=5π/6\displaystyle 2x=5\pi/6. If you consider the next possible correct answer, 2x=2π+π/6=13π/6\displaystyle 2x=2\pi+\pi/6=13\pi/6 then x=13π/12\displaystyle x=13\pi/12, and is still in the interval \(\displaystyle \[0, \2\pi]\). Same for 2x=17π/6\displaystyle 2x=17\pi/6.

That is what the domain for 2x is "twice the size" (although these words are technically incorrect to use) than that of x.
 
Top