Is it possible to have different quadratic equations with the same solution?
B bottomsup2526 New member Joined Aug 22, 2008 Messages 3 Oct 29, 2008 #1 Is it possible to have different quadratic equations with the same solution?
M masters Full Member Joined Mar 30, 2007 Messages 378 Oct 29, 2008 #2 bottomsup2526 said: Is it possible to have different quadratic equations with the same solution? Click to expand... How about if you change the signs....? Will the zeros be the same? How does the parabola change? \(\displaystyle x^2+5x+6=0\) and \(\displaystyle -x^2-5x-6=0\)
bottomsup2526 said: Is it possible to have different quadratic equations with the same solution? Click to expand... How about if you change the signs....? Will the zeros be the same? How does the parabola change? \(\displaystyle x^2+5x+6=0\) and \(\displaystyle -x^2-5x-6=0\)
D Deleted member 4993 Guest Oct 29, 2008 #3 bottomsup2526 said: Is it possible to have different quadratic equations with the same solution? Click to expand... It is possible to have different quadratic functions with same x-intercepts. \(\displaystyle f(x) \, = \, A\cdot (x \, - \, p)\cdot (x \, - \, q) \(\displaystyle Now you can change the value of "A" - to change the shape of the parabola - but the 'x-intercepts' will remain same. Notice the 'y' intercepts will change with the value of 'A'. So when you have quadratic equation [f(x)=0], "A" is divided out and it reduces to same equation every time.\)\)
bottomsup2526 said: Is it possible to have different quadratic equations with the same solution? Click to expand... It is possible to have different quadratic functions with same x-intercepts. \(\displaystyle f(x) \, = \, A\cdot (x \, - \, p)\cdot (x \, - \, q) \(\displaystyle Now you can change the value of "A" - to change the shape of the parabola - but the 'x-intercepts' will remain same. Notice the 'y' intercepts will change with the value of 'A'. So when you have quadratic equation [f(x)=0], "A" is divided out and it reduces to same equation every time.\)\)