question about natural logs

jwpaine

Full Member
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Mar 10, 2007
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Hi.

Question1: Why is it when I enter log(27)/log(3) (both in base 10) that my calculator, (when set on exact) reduces it to ln(3)/ln(2)

is the natural log ln a standard when reducing? I find that quite odd... because ln is the inverse of the natural base e.....


Question2: How would I convert log(27)/log(3) into ln(3)/ln(2)

Thanks.
 
Hello, jwpaine!

I don't know exactly how you're entering the problem,
. . but your calculator is wrong.

By the way, how do you know that reduces to \(\displaystyle \frac{\ln3}{\ln2}\)?
. . Is that thing displayed?


Why is it when I enter log(27)/log(3) (both in base 10)
that my calculator (when set on exact), reduces it to ln(3)/ln(2) . Not true!

We have: \(\displaystyle \L\:\frac{\log(27)}{\log(3)} \:=\:\frac{\log(3^3)}{\log(3)} \:=\:\frac{3\cdot\log(3)}{\log(3)} \:=\:3\)

 
Hi Soroban!

Thanks for your reply.
I made a typo: I meant to say a different rational... but now I can't even find what one I had

Let me make up a different one, and then restate my question: When my ti-89 reduces logs... if it the answer is irrational (and when the mode is set on exact) it reduces it to ln.
Is reducing an irrational answer to a natural log, ln, a standard for reduction in the mathematical community?

Lets do the sum of two logs:
log(4) + log(3)

My calculator says ln(12)/ln(10)

Question 1: is this a standard for reduction in the mathematical community?
Question 2: How do I preform this odd change of base. Why would I want to go from base 10, to a natural log? It doesn't make sense to me.

how do I go from log(12) to ln(12)/ln(10) and why is this a good/bad/acceptable answer

Thanks a TON!
 
This is point Soroban is making: \(\displaystyle \L \log _b (a) = \frac{{\ln (a)}}{{\ln (b)}}\).

Thus \(\displaystyle \L \log (4) + \log (3) = \log (12) = \frac{{\ln (12)}}{{\ln (10)}}\).

This is a soapbox of mine. Many current authors are beginning to use log in any place historically ln has been used. Leonard Gillman (an ex-president of the MAA) introduced me to that possibility in the early 1970’s. Professor Gillman went from the University of Rochester to be chairman at Texas. Now I know that the TI92 is based on Derive as its CAS. There may be some connection there.
BTW: I absolutely agree with doing what Gillman has done. In complex variables there is only one logarithm, log. But here is a little story. About twenty years ago, I was teaching an analysis graduate course for in-service teachers. Among the students was the chairwoman of the chemistry department of a local college. When I gave my little talk why there is only one log, she became so angry that she never came back. It seems that chemist need base 10.
 
I've heard of "log()" meaning "log<sub>10</sub>()", "log<sub>e</sub>()", and "log<sub>2</sub>()". In a context such as this forum, it's probably best always to ask and/or to specify.

Eliz.
 
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