Hi.
Question1: Why is it when I enter log(27)/log(3) (both in base 10) that my calculator, (when set on exact) reduces it to ln(3)/ln(2)
is the natural log ln a standard when reducing? I find that quite odd... because ln is the inverse of the natural base e.....
Question2: How would I convert log(27)/log(3) into ln(3)/ln(2)
Thanks.
Question1: Why is it when I enter log(27)/log(3) (both in base 10) that my calculator, (when set on exact) reduces it to ln(3)/ln(2)
is the natural log ln a standard when reducing? I find that quite odd... because ln is the inverse of the natural base e.....
Question2: How would I convert log(27)/log(3) into ln(3)/ln(2)
Thanks.