Quadrilateral ABCD

[jayjay12]

Given: Quadrilateral ABCD is a rectangle with DX || YB. Prove:Triangle AXD congruent to Triangle CYB

Statment: ABCD is a rectangle. (given) angle DAX and angle BCY are right angles. (given reason)

I need some help some problem. I got it wrong and I would like to now what was the correct answer. May some one plz help me.

 

[TchrWill]

Given: Quadrilateral ABCD is a rectangle with DX || YB. Prove:Triangle AXD congruent to Triangle CYB

AD = BC
?_AXD = /_CYB
AX = AD/tan(/_AXD)
Therefore, CY = AX making DX = BY
The triangles are therefore congruent.

 

[jayjay12]

Thank you for the help.