Quadratic Word Problem: find four consec. odd integers....

[Richay]

Find four consecutive odd integers such that the product of the third and fourth is 49 greater than the product of the first and the number 10.

Answer in the form: a, b, c, d and e, f, g, h (smallest to largest)

5, 7, 9, 11 is one solution (Right?)

But I don't know the other. Help please

 

[skeeter]

four consecutive odd integers ...

n, n+2, n+4, and n+6

product of the third and fourth is 49 greater than the product of the first and the number 10

(n+4)(n+6) = 49 + 10n

n² + 10n + 24 = 49 + 10n

n² - 25 = 0

(n - 5)(n + 5) = 0

n = 5 or n = -5

5, 7, 9, 11 and -5, -3, -1, 1

 

[Richay]

Oh I see. thank you