So, this one won't factor, so I use the Quadratic Formula, right? 8sin^2(x)+5sin(x)-1=0
G ginamarie313 New member Joined Nov 21, 2005 Messages 5 Nov 21, 2005 #1 So, this one won't factor, so I use the Quadratic Formula, right? 8sin^2(x)+5sin(x)-1=0
G ginamarie313 New member Joined Nov 21, 2005 Messages 5 Nov 21, 2005 #3 how do i plug it into the formula is my question
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Nov 21, 2005 #4 Same as always: a = 8, b = 5, c = -1, and x (or, in this case, sin(x)) is given by: . . . . .\(\displaystyle \Large{\frac{-b\mbox{ }\pm\mbox{ }\sqrt{b^2\mbox{ }-\mbox{ }4ac}}{2a}}\) Once you've solved for what sin(x) equals, then solve the resulting two trig equations for what x equals. Eliz.
Same as always: a = 8, b = 5, c = -1, and x (or, in this case, sin(x)) is given by: . . . . .\(\displaystyle \Large{\frac{-b\mbox{ }\pm\mbox{ }\sqrt{b^2\mbox{ }-\mbox{ }4ac}}{2a}}\) Once you've solved for what sin(x) equals, then solve the resulting two trig equations for what x equals. Eliz.