Quadratic Problem

[varun_kanpur]

I am unable to find the answer of this question. Any help will be appreciated

If A^2 + B^2 =1 then find the range of (a+b) where a and b is real.

 

[JeffM]

I am unable to find the answer of this question. Any help will be appreciated

If A^2 + B^2 =1 then find the range of (a+b) where a and b is real.

This is one of those questions that tests your understanding of concepts; there is no standard method of solving.

If A is real and A^2 > 1, what is the sign of B^2?

How far can you go from that hint?

Please show your work in your response.

 

[Deleted member 4993]

I am unable to find the answer of this question. Any help will be appreciated

If A^2 + B^2 =1 then find the range of (a+b) where a and b is real.

You have 'A' & 'a' along with 'B' and 'b'.

Does question as posted make sense?

 

[lookagain]

If we assume a <> b, and assume b > a, then:
a^2 + > > > (b+x)^2 < < < = 1
leads to:
x = -a +- SQRT(1 - a^2)

Denis, that expression must be (a + x)^2, because you were replacing b with (a + x), with your assumption that b > a.