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Quadratic Functions
- Thread starter vlawson
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vlawson said:I am having trouble with quadratic functions.
My homework states write a quadratic function in vertex form that has the given vertex and passes through the given point. Vertex: (6,-6) Point: (8, -14)
That would be equation of a parabola.
Please show us your work, indicating exactly where you are stuck - so that we may know where to begin to help you.
vlawson said:I am having trouble with quadratic functions.
My homework states write a quadratic function in vertex form that has the given vertex and passes through the given point. Vertex: (6,-6) Point: (8, -14)
Hi vlawson,
Start with the vertex form of the quadratic function: \(\displaystyle y=a(x-h)^2+k\), where (h, k) represents the vertex of the parabola.
Next, substitute your vertex (6, -6) in place of h and k: \(\displaystyle y=a(x-6)^2-6\)
Since you know a point on the curve, you can substitute those coordinates for x and y. Then solve for a.
Now you have all you need to define the equation.